Nick wrote:
Just needs to remember Ia ≠Ik in the case of A2
'cos current flow is out through the grid too in A2? So Ia = Ig + Ik?DTB
Red spots appeared on 300B anode
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Dave the bass
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#31
'cos current flow is out through the grid too in A2? So Ia = Ig + Ik?DTB
"The fat bourgeois and his doppelganger"
#32
Yep, your light bulb is correct sir, or
Ik = Ig + Is + Ia
for a pentode.
In fact
Ik = Ig + Ia
Is always true for a triode, but in A1 Ig = 0
Ik = Ig + Is + Ia
for a pentode.
In fact
Ik = Ig + Ia
Is always true for a triode, but in A1 Ig = 0
Whenever an honest man discovers that he's mistaken, he will either cease to be mistaken or he will cease to be honest.
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Mike H
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#33
I know, but sometimes you have to persevere more:Nick wrote:Thats what I saidMike H wrote:Va - Vk x Ia. Seemples!
"Look, V.." <slap> "a.." <slap> "minus.." <slap> "V.." <slap> ....
"No matter how fast light travels it finds that the darkness has always got there first, and is waiting for it."